Learn Everything About Roman Numerals | From Basics to Advanced Learning | Quiznest.in

1. Introduction to Roman Numerals:

1.1

Roman numerals are an ancient numeral system originating from ancient Rome. Unlike our modern decimal system, Romans used combinations of letters from their alphabet to represent numbers.

1.2

In Roman Numerals, alphabets are used to denote numbers. A total of 7 alphabets are used to denote numbers. The basic symbols include: I (1), V (5), X (10), L (50), C (100), D (500) and M (1000).

1.3

Each symbol carries a specific value, and numbers are formed by combining these symbols. You have to employ additive and subtractive principles to form Roman numerals.

1.4

Additive principles to form Roman numerals:
2 is represented by II (1+1) and
3 is represented by III (1+1+1)

1.5

Subtractive principles to form Roman numerals:
4 is represented by IV (5-1) and
9 is represented by IX (10-1)

2. Simple Roman Numerals:

2.1

Roman numerals from 1 to 5:
I (1)
II (1+1)
III (1+1+1)
IV (5-1)
V (5)

2.2

Roman numerals from 6 to 10:
VI (5+1)
VII (5+1+1)
VIII (5+1+1+1)
IX (10-1)
X (10)

2.3

Roman numerals from 11 to 15:
XI (10+1)
XII (10+1+1)
XIII (10+1+1+1)
XIV (10+4)
XV (15)

2.4

Roman numerals from 16 to 20:
XVI (10+6)
XVII (10+7)
XVIII (10+8)
XIX (10+9)
XX (20)

2.5

Roman numerals from 21 to 25:
XXI (20+1)
XXII (20+2)
XXIII (20+3)
XXIV (20+4)
XXV (20+5)

2.6

Roman numerals from 26 to 30:
XXVI (20+6)
XXVII (20+7)
XXVIII (20+8)
XXIX (20+9)
XXX (20+10)

3. Let's Form Roman Numerals:

3.1

To form 90, we have to use
100 (C) and 10 (X) only.
So, 90 = 100 - 10 = C - X = XC
(Subtractive principle)

3.2

To form 110, we have to use
100 and 10 only.
Roman symbol for
100 is C and for 10 is X.
So, 110 = 100 + 10 = C + X = CX
(Additive principle)

3.3

To form 89, we have to use
50 (L), 10 (X) and 1 (I).
So, 89 = 50 + 10 + 10+ 10 + (10-1)
= L + X + X + X + (X-I)
= LXXXIX
In Roman numerals, 89 is written as LXXXIX.

3.4

To form 92, we have to use
100 (C), 10 (X) and 1 (I).
So, 92 = (100 - 10) + 1 + 1
= (C - X) + I + I
= XCII
In Roman numerals, 92 is written as XCII.

3.5

To form 112, we have to use
100 (C), 10 (X) and 1 (I).
So, 112 = 100 + 10 + 1 + 1
= C + X + I + I
= CXII
In Roman numerals, 112 is written as CXII.

3.6

To form 512, we have to use
500 (D), 10 (X) and 1 (I).
So, 512 = 500 + 10 + 1 + 1
= D + X + I + I
= DXII
In Roman numerals, 512 is written as DXII.

3.7

To form 1012, we have to use
1000 (M), 10 (X) and 1 (I).
So, 1012 = 1000 + 10 + 1 + 1
= M + X + I + I
= MXII
In Roman numerals, 1012 is written as MXII.